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g) $ e C B # 3 T 1 (1 " r B E @) 1 (0. F '. 8 8 G. 8 8 G. G G . V (A 2 " ` (A 1 " A i " C B A) (0 r B E @) 1 (0. F '. H I G 8 8 H. H I G. If a, b, and c are vectors and c is a scalar, then. 1. a x b = –b x a. 2. (ca) x b = c(a x b) = a x (cb). 3. a x (b + c) = a x b + a x c. 4. (a + b) x c = a. Note that the sum of cA and cB is constant. d(cA + cB) dt. = RA + RB = 0. Therefore, cA + cB is a constant. CB(T T /,X#O. 91!"#!!!"# %&'()*(+!#-!". %&'()*(+!#-!". TCI".-!"#. TCD[F E S 6$%:A$"!":'&"=?: " P9&6 " M&G&R& &"' =?: " P9&6 " P%$@%& OP%$@%& $#0& '1. Note that the sum of cA and cB is constant. d(cA + cB) dt. = RA + RB = 0. Therefore, cA + cB is a constant. ^а Za Za ^. A fS sA A A ^ A sZ A ^ A. yZZfAr\ a a a y. If A = B, then CA = CB. Right multiplication: If A = B, then AC = BC XA = B, X = A-1B X = BA AX = B, X = BA X = A-1B. AX = BA, X = A. es L\à\. oL C\etic- c-No&\t,c\ c& SiX\eI. QcDçec re o ek o - ç-cn. ___"AON k Cc\t c \xA. \' er. U1 o ccc& c c c-\ co cxd\ cj çç \ç\. 1 ccithco oftc. \ COcLAV. ES-, CCCP-, Estonia. ET-, Ethiopia, EW-, CCCP-, Belarus. EX-, CCCP-, Kyrgyzstan XA-, Mexico, , Commercial. XB-, Mexico, , Private. XC-.
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AB = CB. Examples a. AB and CB are tangent to circle D. Find the value of x. ABE CB x+15=2x 20=x if. 2 segments are tangent to the. Figure. A. B. C. A. e e 0 c b e 0 e b c. b b c 0 e b 0 b e c. c c b e 0 c 0 c c 0. Assume s = a, x = a. ⇒ s + x = 0 s = b, x = b. ⇒ s + x = 0, so Axiom (5) is also verified.
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